Question

71.
The energy required to ionise a helium atom is equal
to 24.6 eV. The energy required to remove both
the electron from the helium atom would be:-
(1) 59 eV
(2) 81 eV
(3) 79 eV
(4) 40 eV​

Answer 1

Answer:

He→He+eIP1=24.6eV  

He⊕→He2++eIP2=?

IP2=13.6eV×Z2=13.6eV×Z2=54.4eV

IP1+IP2=24.6+54.4=79eV

Explanation: