Question

72 litres of liquid A and 108 litres of liquid B are to be packed in containers of same size. find the minimum number of containers required.

Answer 1

Here, we will find the HCF of 72 and 108.

Now, HCF of 72 and 108 is 36.

Total quantity of the liquids is 180.

Minimum no. of containers required is 180/36 = 5

Hope this helps you out.

Answer 2

Answer: There are 5 minimum number of containers required.

Step-by-step explanation:

Since we have given that

Quantity of liquid A = 72 ltrs

Quantity of liquid B = 108 ltrs

We need to find the minimum number of containers required.

Total quantity of liquid = L.C.M. of 72 and 108 = 180

So, We will do H.C.F. of 72 and 108 to get the minimum number of containers.

H.C.F. of 72 and 108 = 36

Hence, minimum number of containers required is $\dfrac{180}{36}=5$.