Question

73)
a
-
2,
Decomposition of N2O5 is first order reaction to of
the reaction N205 -> 2NO, + = 0, is 2.4 hr at
STP. Starting with 10.8 gm of N2O5, how much
oxygen will be obtained after a period of 9.6 hr?
(1) 1.5 litre
(2) 3.36 litre
(3) 1.05 litre
(4) 0.07 litre​

Answer 1

The volume of oxygen obtained is "V" = 0.07 L

Option (4) is correct.

Explanation:

Given data:

Time "t" = 9.6 hour

n =  9.6 / 2.4 = 4

The volume of obtained is = V / 2^4 = V / 16

108 gram produces 22.4 L x 1/2

10.8 g produces 2.24 L x 1/2

Therefore V = 2.24 / 2 x 16 = 0.14 / 2

Volume "V" = 0.07 L

Thus the volume of oxygen obtained is "V" = 0.07 L

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