Question

735 L of a solution containing 0.34 moles of calcium hydroxide

Answer 1

First we have to calculate the concentration of the strong acid HNO3:

0.34molHNO3735L=4.626×10−4M

Now HNO3 is a strong acid, and dissociates completely in water: HNO3 → H+ + NO3-.

[H+]pH=4.626×10−4M=−log[H+]=−log[4.626×10−4]=3.33

Despite the large dilution factor (a small number of moles into 735 Liters), this is still quite an acidic solution, pH < 7.