Question

Show that the diagonals of a square are equal and bisect each other at right angles.​

Answer 1

Answer:

given ABCD is a square

prove AC = BD,OA=OC

Step-by-step explanation:

proof . in triangle BAD and CAD

AD =AD(COMMON)

AB = CO( sides of square )

angle C = angle A (each 90 degree)

by SAS rule

triangle BAD is congruent to triangle

hence, BO=AC (by CPCT)

every square is parallelogram diagonal bisect each other

= OA = OC, OB=OD

in triangle ADB and triangle COB

AB= CB

OB=OB(COMMON)

OA =OC (PROVED ABOVE)

BY SSS RULE

triangle ABC is congruent to triangle COB

angle AOB +angle COB=180 DEGREE

angle AOB+angle AOB=180 DEGREE

twice of angle AOB =180 DEGREE

angle AOB= 180/2=90 DEGREE

THERE FORE, AOB=90 DEGREE

HENCE, PROVED

Answer 2

Answer:

here is your answer plzz mark me as brainleist.