Question

74.5 of a metaallic chloride contains 35.5 g of chlorine. the equivalent mass of a metal is?

Answer 1

35.5 g of chlorine is present in 74.5 g of this metallic chloride

Which means that there is one mole of chlorine atoms in the metal chloride

So, one chlorine gets one electron

And the formula for equivalent weight is:

$\frac{Molar\:\:mass\:\:of \:\:compound}{no.\:\:of\:\:electrons\:\:gained}$

Since one electron is gained

$\frac{74.5}{1}$ = 74.5 is your answer

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Answer 2

$\checkmark$ Given:

74.5 g of a metallic chloride contains 35.5 g of chlorine

$\checkmark$ To Find:

The equivalent mass of metal

$\checkmark$ Solution:

We know that,

$\red{\longrightarrow \sf MX=M+X}$

Here,

• MX = mass of metal chloride
• M = mass of metal
• X = mass of chloride

Given that,

74.5 g of a metallic chloride contains 35.5 g of chlorine

Hence,

• MX = 74.5 g
• X = 35.5 g

Substituting the values,

We get,

$\blue{\sf \longrightarrow 74.5 = M+35.5}$

$\green{\sf \longrightarrow 74.5-35.5 = M}$

$\orange{\sf \longrightarrow M=(74.5-35.5) \ g}$

So,

$\pink{\sf \longrightarrow M=39 \ g}$

Therefore,

$\star$ Mass of metal = 39 g

According to the Question,

We are asked the equivalent mass of metal

We know that,

$\red{\sf \longrightarrow E =\dfrac{M}{X} \times w}$

Here,

• E = equivalent weight of metal
• M = mass of metal
• X = mass of chlorine
• w = molar mass of chlorine

Given that,

74.5 g of a metallic chloride contains 35.5 g of chlorine

Hence,

• X = 35.5 g

We found out that,

• M = 39 g

We know that,

Molar mass of chlorine is 35.5 g

Hence,

• w = 35.5 g

Substituting the values,

We get,

$\blue{\sf \longrightarrow E= \left(\dfrac{39}{35.5} \times 35.5 \ \right) g}$

Cancelling similar terms,

We get,

$\green{\sf \longrightarrow E=(39 \times 1) \ g}$

So,

$\pink{\sf \longrightarrow E=39 \ g}$

Therefore,

$\star$ Equivalent mass of metal = 39 g