Question

A car initially at rest attains a velocity of 20 m/s in a time interval of 5 second. Find acceleration of the car.

Answer 1

Answer:

a = 4 m /$s^{2}$

Explanation:

⇒ u = 0 m/s

⇒ v = 20 m/s

⇒ t = 5sec

⇒ a = ?

Equation used :

⇒ v = u + at

⇒ 20 = 0 + a × 5

⇒ 20/5 = a

⇒ 4 $m/s^{2}$ = a

Answer 2

Answer :

➥ Acceleration of the car = 4 m/s²

Given :

➤ Intial velocity of the car (u) = 0 m/s

➤ Final velocity of the car (v) = 20 m/s

To Find :

➤ Acceleration of the car (a) = ?

Solution :

Acceleration is given by

$\tt{: \implies a = \dfrac{v - u}{t} }$

$\tt{: \implies a = \dfrac{20 - 0}{5} }$

$\tt{: \implies a = \cancel{ \dfrac{20}{5} }}$

$\tt{: \implies \green {\underline{ \overline{ \boxed{ \purple{ \bf{ \: \: a = 4 \:m/s^2 \: \: }}}}}}}$

Hence, the acceleration of the is 4 m/s².

$\:\:\:\:$

Additional Information :

What is acceleration ?

➜ Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

What is Instantaneous acceleration ?

➜ The ratio of change in velocity during a given time interval such that the time interval goes to zero.

What is the formula of acceleration ?

➜ $\sf{a = \dfrac{v - u}{t} }$

➜ $\sf{\dfrac{Change\: in\: velocity }{time}}$

➜ $\sf{a = \dfrac{v_f - u_i}{t} }$

Where,

• a is the acceleration
• v is final velocity
• u is intial velocity
• t is time taken
• $\sf v_f$ is final velocity
• $\sf u_i$ is intial velocity