75.2 g of phenol is dissolved in 1 kg of solvent of kf=14 if the depresssion in frezeng point is 7k then find the %phenol that demerises
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Mb =
Taking the solvent as 1 kg
Mb =
= 150.4 g per mol
phenol (molar mass) — 94 g/mol
i =
i = 94 / 150.4 = 0.625
We have, 2C6H5OH ↔ (C6H5OH)2
1 0
1- α α/2
Total = 1- α + α/2
i = 1- α/2
0.625 = 1- α/2
α/2 = 0.375
α = 0.375/2
α = 0.75
% of phenol that dimerizes = 75%
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