√(75) - √(27) solve correctly please
aleeza2108:
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Here we have to solve ,
First of all expand these terms inside the square root by taking LCM.
Now, take out the numbers which are two times on product inside the same square root.
So, take 5 and 3 out if square root.
= 5✓3 - 3✓3
Taking common ✓3
= ✓3 (5-3)
Subtract 3 from 5.
= 2✓3
Therefore,
= 2✓3
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