75 ml, M/5 HCL + 25ml, M/5 NaOh. Find ph of the solution.
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pH of a solution is the negative logarithm to base 10 of the activity of hydrogen ion
P(H)=-log[H^{+}]
As N1V1 > N2V2 so acid left at the end of reaction
N_{mixture} = [H]^{+} =\frac{N_{1}V_{1} - N_{2}V_{2}}{V_{1} + V_{2}} = \frac{\frac{1}{5}X75 - \frac{1}{5}X25 }{75+25} = \frac{1}{10} = 10^{-1}
pH = -log10^{-1} = 1
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