Question

75 passengers are traveling in a bus. Some passengers are carrying 5 rupee tickets and remaining are carrying 10 rupee tickets. the total fare recieved by the bus driver is 580 rupee. find the number of passengers carrying 5 and 10 rupee tickets​

Answer 1

Answer:

Passengers carrying 5 ₹ ticket = x = 34.

passengers carrying 10 ₹ ticket = 75 - x = 75 - 34 = 41

Step-by-step explanation:

Let the number of passengers carrying Rs 5 tickets be a

So total number of passengers are 75.

Now the number of passengers carrying Rs 10 tickets will be 75 – x

According to question total amount collected by the conductor is Rs. 580.

Thus,

5x + 10(75 – x) = 580

 =>  5x + 750 – 10x = 580

=>    5x – 10x = 580 – 750

=>    -5x = - 170

=>     x = (-170) / (-5) = 34

Hence, x = 34

Thus passengers carrying 5 ₹ ticket = x = 34

And passengers carrying 10 ₹ ticket = 75 - x = 75 - 34 = 41

Answer 2

Answer:

34 and 41

Step-by-step explanation:

75passengers are travelling in a bus. Some passengers are carrying 5 tickets and remaining are carrying 10 tickets. The total fare received

by the conductor is 580.Find the number of passengers carrying:

a. 5 ticket b. 10 ticket

Let the number of passengers carrying Rs 5 tickets be a

So total number of passengers are 75

Now the number of passengers carrying Rs 10 tickets will be 75– x

According to question total amount collected by the conductor is Rs 580

So 5x + 10(75 – x) = 580

5x + 750 – 10x = 580

5x – 10x = 580 – 750

-5x = - 170

So x = 34

Now the number of passengers carrying Rs 5 tickets will be 34 and number of passengers carrying Rs 10 tickets will be 75 – 34 = 41