Question

77
The dipole moment of HBr is 1.6 x 10-30 cm and
inter - atomic spacing is 1 A. The % ionic character of
HBr is
(1)5 (2) 10 (3) 15 (4) 27​

Answer 1

Answer:

The bond dipole moment uses the idea of electric dipole moment to measure the polarity of a chemical bond within a molecule. It occurs whenever there is a separation of positive and negative charges.

Answer 2

$\huge\mathcal{ \overbrace{ \underbrace{ \pink{ \fbox{ \green{ \blue{A} \pink{n} \red{s} \green{w} \purple{e} \blue{r}}}}}}}$

$Charge \: of \: electron(q) \: = 1.6 \times {10}^{ - 19} \: c \\ Dipole \: moment \: of \: HBr \: = 1.6 \times {10}^{ - 30} \: m \\ Inter - \: atomic \: spacing = 1Å = 1 \times {10}^{ - 10} \: m\\ \\ \% \: of \: ionic \: character \: in \: HBr \\ \\ = \frac{Dipole \: moment \: of \: HBr \times 100}{Inter - spacing \: distance \: \times q} \\ \\ = \frac{1.6 \times {10}^{ - 30} \times 100 }{1.6 \times {10}^{ - 19} \times {10}^{ - 10} } \\ \\ = 10\%$

Hence, option (2) is correct