Question

78.
Number of electrons in 10 C of charge is
(A) 6.25 10
(C) 6* 10%
(B) 6 25 10
(D) 6 x 10​

Answer 1

Answer:

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Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

Charge (q) = 10 C

We know that ,

The charge on a body is integral multiple of electrons

$\large \mathtt{ \fbox{Charge \: (q) = ne}}$

Thus ,

$\sf \hookrightarrow 10 = n \times 1.9 \times {(10)}^{ - 19} \\ \\ \sf \hookrightarrow n = \frac{10}{1.9 \times {(10)}^{ - 19}} \\ \\ \sf \hookrightarrow n = 0.625 \times {(10)}^{20} \\ \\ \ \sf \hookrightarrow n = 625 \times {(10)}^{17}$

Hence , the number of electrons is 625 × (10)^17

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