Question

(7a-4t) ki whole cube By using indetities​

Answer 1

HEY MATE MARK AS BRAINLIST IF IT HELPS YOU

SO LETS START

ACCORDING TO QUESTION

WE HAVE TO FIND  

$(7A-4T)^{3$

SO

(a-b)³=a³-3a²b+3ab²-b CUBE

HERE

A=7A

B=4T

THEN

7A CUBE- 3 * 7A SQUARE * 4T + 3* 7T* 4T SQUARE- 4T CUBE

SOLVE IT AND YOU WILL GET THE ANSWER

Answer 2

Answer:

343(a^3) -- 588t(a^2) + 336a(t^2) + 64(t^3)

Step-by-step explanation:

(7a-4t)^3

Using the identity: a^3-(3a^2×b)+(3ab^2)+b^3

Here,a=7a

b=4t

Therefore,

a^3-(3a^2×b)+(3ab^2)+b^3

= (7a)^3-{3(7a)^2×(4t)}+{3(7a)×(4t)^2}+(4t)^3

= 343(a^3) -- 588t(a^2) + 336a(t^2) + 64(t^3)