(7a-6b)-16c² factorise using algebraic expression
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Step-by-step explanation:
m(7a-b)^2-16c^2
7a-6b^2-(4c) ^2
By a^2-b^2=a-b) (a+b) identity
(7a-6b+4c) (7a-6b-4c) is the answer
Hope it helps Mark as brainlliest pls
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