Question

(7a-6b+5c)^3 solve this answer step by step ​

Answer 1

Answer:

(a+b+c)³=a³+b³+c³+3a²b+3a²c+3ab²+3b²c+3ac²+3bc²+6abc

(a+b+c)³=(a³+b³+c³)+(3a²b+3a²c+3abc)+(3ab²+3b²c+3abc)+(3ac²+3bc²+3abc)−3abc

(a+b+c)³=(a³+b³+c³)+3a(ab+ac+bc)+3b(ab+bc+ac)+3c(ac+bc+ab)−3abc

(a+b+c)³=(a³+b³+c³)+3(a+b+c)(ab+ac+bc)−3abc

(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]

here you can put a = 7a, b = -6b, c = 5c

thank you hope this helps sorry I haven't done the calculation.