7a3+56b3 factorize it
Answers
Answered by
129
x^3+y^3=(x+y)(x^2-xy+y^2)
7a^3+56b^3
=7(a^3+8b^3)
=7[a^3+(2b)^3]
=7(a+2b)[a^2-2ab+(2b)^2]
=7(a+2b)(a^2-2ab+4b^2)
7a^3+56b^3
=7(a^3+8b^3)
=7[a^3+(2b)^3]
=7(a+2b)[a^2-2ab+(2b)^2]
=7(a+2b)(a^2-2ab+4b^2)
Answered by
52
Step-by-step explanation:
7a^3 + 56b^3
7(a^3 + 8b^3)
7(a^3 + (2b)^3)
7(a+2b) (a^2-2ab+(2b)^2)
7(a+2b) (a^2 - 2ab + 4b^2)
hope it helps
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