Question

7g of n2,8g of o2,and 22g of co2 mixed.the mole fraction of o2 in the mixture is

Answer 1

Moles of N2 = 7/28 = 0.25
Moles of 02 = 8/32 = 0.25
moles of CO2 = 22/44 = 0.5

Now mole fraction of O2 = 0.25/1.00 = 0.25
,

Answer 2

Answer:

The mole fraction of O2 in the mixture is 0.25.

Explanation:

Given Data :

Weight of Nitrogen ( N2) = 7 gm

Weight of Oxygen ( O2) = 8 gm

Weight if Carbon di oxide (CO2) = 22 gm

Formula to be used :

$number \: of \: moles = \frac{given \: weight}{molar \: mass}$

$mole \: fraction = \frac{number \: of \: moles \: f \: th \: molecule \: }{total \: number \: of \: moles \: in \: the \: mixture \: }$

Calculations :

Molar mass of Oxygen molecule = 32 gm

Molar mass of Nitrogen molecule = 28 gm.

Molar mss of Carbon dioxide= 44 gm

Number of moles of Nitrogen =

$\frac{7}{28} = 0.25$

Number of moles of Oxygen =

$\frac{8}{32} = 0.25$

Number of moles of Carbon di oxide =

$\frac{22}{44} = 0.5$

Hence, the mole fraction of Oxygen in the mixture =

$mole \: fraction \: = \frac{0.25 }{0.25 + 0.25 + 0.5} = \frac{0.25}{1.00} = 0.25$

Hence, the mole fraction of Oxygen is 0.25 .

# SPJ3

Answer 3

The mole fraction of O2 in the mixture is 0.25 moles

Explanation:

• The unit of concentration is the Mole fraction.
• Here in the solution, the relative amount of solute and solvents will be measured by the mole fraction and it will be  represented by “X.”
• The mole fraction is the total number of moles of a component in the solution which is obtained by dividing by the total number of moles in the given solution.

        Here given 7g of n2, 8g of o2,and 22g of co2  are mixed

        Then  the Moles of $N2$= 7/28 = 0.25

         Moles of $02$ = 8/32 = 0.25

        moles of $CO2$ = 22/44 = 0.5

        Total moles =0.25+0.25 = 0.5 moles

       mole fraction of O2 = 0.25/0.25+0.25+.5 = 0.25 moles

       The mole fraction of o2 in the mixture is 0.25 moles

#SPJ3