Question

7g of N2 is allowed to react with 2g H2 in presence of catalyst of form NH3 which is the limiting reagent?​

Answer 1

Explanation:

N2 + 3H2--->2NH3

No of moles of H2= 1mol

No of moles of N2=0.25 mol

According to reaction 1 mol of N2 reacts with 3 mol of H2

here 0.25 mol of N2 requires 0.75 mol of H2

then 0.25 mol of H2 is excess

Here limiting reagent is N2