7gm of sulphur is dissolved in 14 gm of carbon di sulphide. Calculate the percentage amount of the sulphur in the solution.
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Given, Carbon disulphide CS
2
Molar mass of CS
2
=12g+32×2g
=12+64g=76g
i.e; 12g of C reacts with 64g of S to form 76g CS
2
Also, in 12g of C forms 76g CS
2
⇒3.0g of C forms
12
76×3
g of CS
2
⇒19g of CS
2
is formed.
Also,
If 76g CS
2
has 64g of S
then, 19g CS
2
will have
76
19×64
g of S
⇒16.0g of S is present.
hope it helps you ✌️✅✅✅
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