Biology, asked by salimkhan8457, 6 months ago

7In dihybrid cross,F2generation offsprings show four different phenotypes while the genotypes are...... Six Nine Eight Sixteen

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Answered by Anonymous
1

Answer:

Explanation:

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In a dihybrid cross where Mendel self  crossed Heterozygous Yellow Round seed plant .

We obtain Phenotypes as:

1.Yellow Round=9

2.Yellow Wrinkled=3

3.Green Round =3

4.Green Wrinkled=1

So,the phenotypic ratio of dihybrid cross would be 9:3:3:1.

Among which 10 offsprings were Parental type that is Yellow Round (9) and Green Wrinkled(1) while 4 were recombinants that is Yellow wrinkled(3) and Green Round (1).

The Genotypic Ratio of the F2 generation is= 1:2:2:4:1:2:1:2:1.

The nine different types of Genotypes are:

1.YYRR

2.YYRr

3.YyRR

4.YyRr

5.YYrr

6.Yyrr

7.yyRR

8.yyRr

9.yyrr.

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