7th std maths problem 6.5 exercise sum 5
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In the given figure, BC represents the unbroken part of the tree. Point C represents the point where the tree broke and CA
represents the broken part of the tree. Triangle ABC, thus formed, is right-angled at B.
Applying Pythagoras theorem in ΔABC,
AC2
= BC2
+ AB2
AC2
= (5 m)2
+ (12 m)2
AC2
= 25 m2
+ 144 m2
= 169 m2
AC = 13 m
Thus, original height of the tree = AC + CB = 13 m + 5 m = 18 m
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