Question

7th term of H.P. is 3/2and its 10 term of 12/17.find the first term of the common difference

Answer 1

as a7=a+6d
and a10=a+9d
so a+6d=3/2          (1)
     a+9d=12/17      (2)
subtract 1 from 2
 we get 3d=12/17-3/2
             3d=-27/34
             d=-9/34
        so substitute d=-9/34 in eq1
    a+6(-9/34)=3/2
   a-27/17=3/2
  a=3/2+27/17
  a=105/34
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