7x+11y=40
9x+7y=30
solve by substitution method
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Answer:
7x+11y=40..........(1)
9x+7y=30............(2)
from equation first
x=(40-11y)/7...........(3)
putting the value of x in equestion second
9×(40-11y)/7+7y=30
(360-99y+49y)/7=30
-50y=210-360
-50y=-150
y=3
putting the value of y in equestion third
x=(40-11×3)/7
x=7/7
x=1
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