Math, asked by RamanRandhawa, 11 months ago

7x-15y =2,x+2y=3 find the value of x and y by substitution method

Answers

Answered by aastha4865
5
heyy mate!!

7x - 15y = 2 ....eq 1
x + 2y = 3 .....eq2

Multiply eq 2 by 7 and subtract them

-15y - 14y = 2-21
-29y = -19
y = 19/29

Putting value of y in eq 2

x + 2*19/29 = 3
x = 3- 38/29
x= 87/29-38/29
x = 49/29

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Answered by thameshwarp9oqwi
1

Answer:

7X - 15Y = 2....(1)

2X + 2Y = 3...(2)

BY SUBSTITUTION METHOD

7X-15Y = 2

7X = 2+15Y

X = 2+15Y / 7

PUTTING VALUE OF X IN EQ(2)

==> 2(2+15Y/7) + 2Y = 3

==> 4+30Y / 7 + 2Y = 3

==> 4+30Y+14Y / 7 = 3

==> 4+44Y  = 7*3

==> 44Y = 21-4

==> 44Y = 17

==> Y = 17/44

PUTTING VALUE OF Y IN EQ(1)

==> 7X-15Y = 2

==> 7X - 15(17/44) = 2

==> 7X - 255 / 44 = 2

==> 308X - 255 = 88

==> 308X = 343

==> X  = 343/308 ==> 49/44

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