Question

7x+5y = 9 and 5x-3y = 13 Elimation method​

Answer 1

$\huge\underline\red{SOLUTION}$

7x+5y = 9 →eq①

5x-3y = 13→eq②

Multiply eq①×3 = 21x+15y=27

Multiply eq②×5 = 25x-15y=65

Solve eq①&②

21x+15y=27

25x-15y=65

_________

46x+0 = 92

☞46x=92

☞x=92/46

☞x=2

Substitute x=2 in eq①

☞7x+5y = 9

☞7(2)+5y= 9

☞14+5y= 9

☞5y=9-14

☞5y= -5

☞y= -5/5

☞y= -1

Therefore, x=2 & y= -1

Hope it helps...

Answer 2

Please view the attachment for your answer....