7x square-12x+5=0 by quadratic formula method
Answers
Answered by
5
7x^2-12x+5=0
a=7
b=. -12
c=5
so , x= √(b^2-4ac)/2a.
= √(-12^2-4×7×5)/2×7.
= √(144-140)/14
=√4/14
=2/14
1/7 is the answer
hope it's help u
plZ mark as brainlist
a=7
b=. -12
c=5
so , x= √(b^2-4ac)/2a.
= √(-12^2-4×7×5)/2×7.
= √(144-140)/14
=√4/14
=2/14
1/7 is the answer
hope it's help u
plZ mark as brainlist
Answered by
0
7x²-12x+5=0
D= b²-4ac = (12)² - 4(7)(5)
=144 - 4(35) = 144-140 =4
x = -b± √d/2a
=12±√4 / 12(7)
= 12±2 /14
⇒x=12+2/14 =14/14
x=1
⇒x =12-2/14 =10/14
x=5/7
∴ the roots are 1 and 5/7.
Similar questions