Question

7x2 - 19x - 6
can anyone answer this question? ​

Answer 1

Answer:

$7 {x}^{2} - 19x - 6 = 0\\ 7 {x}^{2} - (21 - 2)x - 6 = 0\\ 7 {x}^{2} - 21x + 2x - 6 = 0\\ 7x(x - 3) + 2(x - 3) = 0 \\ (7x + 2)(x - 3) = 0 \\ if \: x - 3 = 0 \\ \: then \\ \: x = 3 \\ \\ and \: if \: 7x + 2 = 0 \\ then \: \\ x = - 2 \div 7 \\ \\ \\ so \: x = 3 \: and \: - 2 \div 7$

Hope it helps you.