Question

(7x²y-3z²) (x+y+z); x=1, y=1, z=-1​

Answer 1

Step-by-step explanation:

$(7 {x}^{2} y - 3 {z}^{2} )(x + y + z) \\ put \: x = 1 \: \: \: y = 1 \: \: z = - 1 \: \: \: \: \: \: \: \: \\ (7(1)(1) - 3(1))(1 + 1 + 1) \\ 4 \times 3 \\ 12$

Answer 2

Step-by-step explanation:

$(7x {}^{2} y - 3z {}^{2} )(x + y + z) \\ (7(1) {}^{2} \times 1 - 3( - 1) {}^{2} )(1 + 1 + ( - 1)) \\ (7 - 3)(1) \\ 4 \times 1 \\ 4 \\ \\ here \: is \: your \: solution$