Math, asked by shaleenamehmood, 10 months ago

7y^2-3=0 solve by square root

Answers

Answered by vyshu625676
1

Answer:

7y^2 =3

y=root7/3

Step-by-step explanation:

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Answered by yashdeep945
0

Answer:7y²-3=0

(√7*y)²-(√3)²=0

(√7y+√3)(√7y-√3)=0

y= -√3/√7and y=√3/√7

hope it helps.....

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