Math, asked by motalipurohit, 1 year ago

7y square - 11/3y-2/3

Answers

Answered by AbhijatPaul
2
y
7 {y}^{2}  -  \frac{11}{3y}  -  \frac{2}{3}
7{y}^{2}  -  \frac{33 - 6y}{9y}
 \frac{63 {y}^{3} - 33 + 6y }{9y}
..
 \frac{3}{3} ( \frac{21 {y}^{3} - 11 + 2y }{3y}  )
Answer
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AbhijatPaul: 3/3 =1
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