√8,√18,√32 find 10th number
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Answered by
2
a2-a1= d = 3√2-2√2= √2
Thus the common difference is √2
And the first term a is √8
an= a+(n-1)d....... formula
a10= 2√2+(10-1)√2
a10= 2√2+9√2
a10= 11√2
Hope this helps you...✌
Thus the common difference is √2
And the first term a is √8
an= a+(n-1)d....... formula
a10= 2√2+(10-1)√2
a10= 2√2+9√2
a10= 11√2
Hope this helps you...✌
DeeptiMohanty:
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Answered by
1
a2-a1= d = 3√2-2√2= √2
Thus the common difference is √2
And the first term a is √8
an= a+(n-1)d....... formula
a10= 2√2+(10-1)√2
a10= 2√2+9√2
a10= 11√2
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