Question

8×2^2x+4×2^x+1=1+2^×​

Answer 1

Answer:

so 2^x = -3/8.

How is it****** x = log^(-3/8)/2

Answer 2

Step-by-step explanation:

8*2^2x+4*2^x+1=1+2^x

8*4+2x+16x+1=5x

32+18x+2=5x

34+18x=5x

by tranposing 5x to that side,we get

18x-5x=-34

13x=-34

x=-34/13

x=-2.61