Question

8. 20 years ago, father was five times as old as his son. After 5 years three times of father's
age will be equal to five times of son's age. What are the present ages of father and son
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Answer 1

Answer:

Step-by-step explanation:

Let son's age = x

20 years ago son's age= x-20

His Father's age at that time = 5(x-20).

Present age of Father = 5x -100+20 = 5x-80

five years hence father's age= 5x-80+5=5x -75

five years hence son's age = x+5.

Given :-5*(x+5)=3*(5x-75)

5x + 25= 15x - 225

25+225=15x-5x

25=x

SON'S PRESENT AGE :25years.

FATHER'S PTESENT AGE:45 years.