Question

8-27b^3-343c^3-126bc factorise​

Answer 1

Answer:

Step-by-step explanation:

   8 - 27b³ - 343c³ - 126bc

= (2)³+(-3b)³+(-7c)³-3(2)(-3b)(-7c)

using formula a³ + b³ + c³ - 3abc = (a + b + c) (a² + b²+ c²- ab - bc - ca)

(2)³+(-3b)³+(-7c)³-3(2)(-3b)(-7c)  

= (2 - 3b - 7c) [(2)² + (3b)² + (7c)²- (2 x -3b) - (-3b x -7c) - (-7c x 2)]

= (2 - 3b - 7c) [4 + 9b² + 49c² + 6b - 21bc + 14c)

Answer 2

Answer:

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