8-27b^3-343c^3-126bc factorise
Answers
Answered by
30
Answer:
Step-by-step explanation:
8 - 27b³ - 343c³ - 126bc
= (2)³+(-3b)³+(-7c)³-3(2)(-3b)(-7c)
using formula a³ + b³ + c³ - 3abc = (a + b + c) (a² + b²+ c²- ab - bc - ca)
(2)³+(-3b)³+(-7c)³-3(2)(-3b)(-7c)
= (2 - 3b - 7c) [(2)² + (3b)² + (7c)²- (2 x -3b) - (-3b x -7c) - (-7c x 2)]
= (2 - 3b - 7c) [4 + 9b² + 49c² + 6b - 21bc + 14c)
Answered by
2
Answer:
PLEASE MARK me as BRAINLIST
Similar questions