Question

8(2a+3b)3-12(2a+3b)2

Answer 1

8 (2a + 3b) ³ - 12 (2a + 3b) ²

⟶ (2a + 3b) ² . 8(2a + 3b) + (12 - 1)

⟶ 16a + 24b - 12 = 4(4a + 6b - 3)

⟶ 4 (2a + 3b) ² - (4a + 6b - 3)

Answer 2

Answer:

$4(4a^{2} +24ab+9b^{2} )[2(2a+3b)-3]$

Step-by-step explanation:

Given : The expression is $8(2a+3b)^{3} -12(2a+3b)^{2}$

To find : We have to simplify the given expression.

Solution :

• The given expression is

       $8(2a+3b)^{3}-12(2a+3b)^{2}$

• Now,take out common factors from both the terms, we get

       $8(2a+3b)^{3}-12(2a+3b)^{2}$ = $4(2a+3b)^{2} [2(2a+3b)-3]$

•  We know that,

        $(a+b)^{2} = a^{2} +2ab+b^{2}$

• Apply this formula in above equation, we get

          $= 4(4a^{2} +24ab+9b^{2} )[2(2a+3b)-3]$

•          ∴ $8(2a+3b)^{3} -12(2a+3b)^{2} = 4(4a^{2} +24ab+9b^{2} )[2(2a+3b)-3)]$