Question

8(3a-2b)²-10(3a-2b)​

Answer 1

Answer:

The factorisation of 8(3a-2b)^2(3a−2b)2-10(3a - 2b) =

2(3a - 2b)(12a - 8b - 5)

Step-by-step explanation:

We have,

8(3a-2b)^2(3a−2b)

2

- 10(3a - 2b)

To find, the factorisation of 8(3a-2b)^2(3a−2b)

2

- 10(3a - 2b) = ?

∴ 8(3a-2b)^2(3a−2b)

2

- 10(3a - 2b)

= (2 × 4) (3a-2b)^2(3a−2b)

2

- (2 × 5) (3a - 2b)

Taking 2(3a - 2b) as common, we get

= 2(3a - 2b)[4(3a - 2b) - 5]

= 2(3a - 2b)(12a - 8b - 5)

∴ The factorisation of 8(3a-2b)^2(3a−2b)

2

- 10(3a - 2b) = 2(3a - 2b)(12a - 8b - 5)