Question

8(3a-2b)2-10(3a-2b)factorize 8thgrade​

Answer 1

Answer:

Given : 8(3a−2b)  

2

−10(3a−2b)

By talking (3a−2b) in the given question, we get,

(3a−2b)[8(3a−2b)−10]

By taking 2 as common in the second term,

(3−2b)2[4(3a−2b)−5]

So we get,

8(3a−2b)  

2

−10(3a−2b)=2(3a−2b)(12a−8b−5)

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