Math, asked by Kshitu73, 7 months ago

(8) 3x² - 2 √6 x + 2 = 0
plz solve this
it's urgent

Answers

Answered by singhkhushmeet309

1

Answer:

3x^2-2√6 x+2

3x^2-√6x-√6x+2

√3x(√3x-√2)-√2(√3x-√2)

(√3x-√2)(√3x-√2)

Answered by iraza

1

Answer:

Step-by-step explanation:

3x² - 2√6x + 2 = 0

3x² - √6x - √6x + 2 = 0

√3x(√3x - √2) - √2(√3x - √2) = 0

(√3x - √2)(√3x - √2) = 0

x = √2/√3 , x = √2/√3

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