Physics, asked by saurabhkumar3011, 11 months ago

8.
(4) 2 v sin 20°
A stone falls from a balloon that is descending at
a uniform rate of 12 ms. The displacement of the
stone from the point of release after 10 sec is :-
(1) 490 m
(2) 510 m
(3) 610 m
(4) 725 m

Answers

Answered by ankitpkalher34
2

Answer:

as the balloon 's velocity is 12 and the stone is released from it so the stone will carry the velocity of balloon

ao the inital velocity of stone is 12m/s.

s=-12×10-1/2× 10 ×100

acxording to the second equatio

=-120-500

=-620m

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