Question

8-4x-2x²+x³ factories​

Answer 1

Answer:

8-4x-2x²+x³ = (2-x)(2+x)(2-x)

Step-by-step explanation:

8-4x-2x²+x³

= 4(2-x)-x²(2-x)

= (2-x)(4-x²)

= (2-x)(2²-x²)

= (2-x)(2+x)(2-x)

Therefore,

8-4x-2x²+x³ = (2-x)(2+x)(2-x)

•••♪

Answer 2

Step-by-step explanation:

We need to factorize 8-4x-2x²+x³. It can be done by rearranging the terms as:

$=8-4x-2x^2+x^3\\\\=4(2-x)-x^2(2-x)\\\\=(4-x^2)(2-x)$

Now using identity

$a^2-b^2=(a-b)(a+b)\\\\(4-x^2)=2^2-x^2=(2-x)(2+x)$

So, the factors will become:

$8-4x-2x^2+x^3=(2-x)(2+x)(2-x)\\\\8-4x-2x^2+x^3=(2-x)^2(2+x)$

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Factors

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