Question

8×5×3=53 , 6×4×6=58,9×3×8=120,5×4×10=?​

Answer 1

Given :-

• 8 × 5 × 3 = 53
• 6 × 4 × 6 = 58
• 9 × 3 × 8 = 120
• 5 × 4 × 10 = ?

A) 173

B) 193

C) 108

D) 161

Solution :-

8 × 5 × 3 = 53

→ 8 + 5 + 3 = 16 => 1 + 6 = 7

→ 5 + 3 = 8

so,

→ 8 - 7 = 1

6 × 4 × 6 = 58

→ 6 + 4 + 6 = 16 => 1 + 6 = 7

→ 5 + 8 = 13 => 1 + 3 = 4

so,

→ 7 - 4 = 3

9 × 3 × 8 = 120

→ 9 + 3 + 8 = 20 => 2 + 0 = 2

→ 1 + 2 + 0 = 3

so,

→ 3 - 2 = 1

as we can see that, difference between sum of digits is in order of 1, 3, 1, 3 .

then, next difference will be 3.

5 × 4 × 10 = ?

→ 5 + 4 + 10 = 19 => 1 + 9 = 10 => 1 + 0 = 1

then,

→ x - 3 = 1

→ x = 4 .

sum of digits will be 4 .

checking options now we get,

A) 173 = 1 + 7 + 3 = 10 => 1 + 0 = 1

B) 193 = 1 + 9 + 3 = 13 => 1 + 3 = 4

C) 108 = 1 + 0 + 8 = 9

D) 161 = 1 + 6 + 1 = 8

therefore, Option (B) 193 is correct answer.

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