8.50g of NH3 is present in 250ml volume . Its active mass is
Najminsultana:
Molar mass nikalna hain kya
This question is taken from chemical equilibrium I asked to find the active mass
Which cls
Answers
Answered by
33
active mass = (wt/Mw) x (1000/V)
wt = weight of solute
Mw = molecular weight of solute
V = volume of solution in ml
so
active mass = (8.5/17) x (1000/250)
active mass = 0.5 x 4 = 2 M
regards
wt = weight of solute
Mw = molecular weight of solute
V = volume of solution in ml
so
active mass = (8.5/17) x (1000/250)
active mass = 0.5 x 4 = 2 M
regards
Answered by
11
Active mass = gram moles per liter of solution
= 8.50/17 *1/0.250 = 2 moles/L or 2 M
Molar mass of Ammonia = 14+3=17
= 8.50/17 *1/0.250 = 2 moles/L or 2 M
Molar mass of Ammonia = 14+3=17
:-) :-)
Tq
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