8*711 in each of the following number replace * by the smallest number to make it divisible by 3
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Answered by
27
if a no is divisible by 3 then the sum of its digits must be divisible by 3
we have
8+*+7+1+1
=17+*
therefore the smallest no to be added is
1
because
17+1=18
1+8=9
and 9 is clearly divisible by 3
we have
8+*+7+1+1
=17+*
therefore the smallest no to be added is
1
because
17+1=18
1+8=9
and 9 is clearly divisible by 3
Answered by
6
Ur ans is here
When I divide 8711 /3
It is coming 2,903.6666666666
When I divide 8711 /3
It is coming 2,903.6666666666
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