Question

8. A bag contains 3 red balls and 5 black balls. A ball is drawn at random from theWhat is the probability that the ball drawn is (i) red ? (ii) not red?​

Answer 1

Hey !

Given,

A bag contains red and black balls

No. of Red balls = 3

No. of Black balls = 5

Let E be the Event that a ball is drawn randomly from bag

and S be the Sample space

Total No. of Balls, n(S)= 8

Probability of occurance of Event 'E' is defined as the ratio of chance of occurance of Event E to the total no. of Outcomes

P(E) = Favorable outcomes/Total No. of Outcomes

=> P(E) = n(E)/n(S)

(i)

Let E be the Event that drawn ball is red

n(E) = 3C1 = 3

n(S) = 8

P(E) = 3/8

•°• Probability that drawn ball is red is 3/8

(ii)

Let E be the Event that drawn ball is not red.

n(E) = 5C1 = 5

n(S) = 8

P(E) = 5/8

•°• Probability that drawn ball is red is 3/8

Meowwww xD