Question

8. A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in
days and C alone in 50 days, then B alone could do it in:
A 15 days
B. 20 days
c. 26 days
D 30 days
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Answer 1

Answer:

answer is C

Step-by-step explanation:

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Answer 2

Answer:

25 days

Step-by-step explanation:

If A completes the work in n days as such by anology B & C together complete the work in same time

Now efficiency of A = 1/n th part of work per day

Combined efficiency of B & C = efficiency of A

E(A) + E(B) + E(C) = 1/n + 1/n = 2/n

Efficiency of A & B = 1/10

Efficiency of C = 1/50

We can write as

E(A) + E(B) +E(C) = 1/10 + 1/50

6/50 = 2/n

n = 100/6

Since E(A) + E(B) = 1/10

E(A) = 6/100

E(B) = 1/10 -6/100 = 4/100 = 1/25

Therefore B will complete the work alone in 25 days

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