Question

A centain amount of so2 gas is introduced into a vessel which already contains oxygen at a pressure of 1 atm when the equilibrium so2
$so2 + 1 \2 o2 gives \: rise \: to \: so3$
is attained. The ratio of Pso3/Pso2 is 10 power of 4 at 1000k. If this mixture is allowed to expand to a volume of four times the original at the same temperature, What is the new value of the ratio of Pso3/Pso2 at equilibrium?​

Answer 1

Answer:

A centain amount of so2 gas is introduced into a vessel which already contains oxygen at a pressure of 1 atm when the equilibrium so2

$so2 + 1 \2 o2 gives \: rise \: to \: so3$

is attained. The ratio of Pso3/Pso2 is 10 power of 4 at 1000k. If this mixture is allowed to expand to a volume of four times the original at the same temperature, What is the new value of the ratio of Pso3/Pso2 at equilibrium?

Explanation:

HOPE it help you my

Answer 2

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The collision of the particles with the walls of the vessels give rise to the pressure of the gas.