Question

8) A circus tent consists of a cylindrical base surmounted by a conical roof. The radius of the cylinder is 30m. the heights of the cylinder& CONICAL PORTIONS ARE RESPECTIVELY 42 M & 21M . Find the volume of the tent.

Answer 1

Volume of cylindrical portion
=
$\pi {r}^{2}h$
=22/7 x 30 x 30 x 42
=22 x 30 x 30 x 6
=118800 meter cube
${118800m}^{3}$
Volume of conical portion
=1/3 πr square h( radius of cylinder = radius of conical part, since conical portion is surmounted on the cylindrical portion)
$1 \div 3\pi {r}^{2} h$
= 1/3 x 22/7 x 30 x 30 x 21
= 22 x 10 x 30 x 3
= 220 x 90
= 19800 meter cube
${19800m}^{3}$
Volume of tent
= Volume of cylindrical portion + volume of conical portion
=118800 + 19800
=138600 meter cube
${138600m}^{3}$