8 a cube + root under 27 b cube
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using the identity a³+b³=(a+b)(a²-ab+b²)
here,
(2a) ³+(√3b)³=(2a+√3b) (4a²-2√3ab+3b²)
hope this helps.......
here,
(2a) ³+(√3b)³=(2a+√3b) (4a²-2√3ab+3b²)
hope this helps.......
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