8) A doctor uses the formula in the box to calculate
patients body mass index (BMI).
BMI=m/h squared where m is the mass in kilo grams and h is the height in metres.
A patient is described as underweight if their BMI is
is the height in metres
below. 18.5
a) Tina's mass is 48.8 kg and her height is 1.56 m. Is she underweight? Explain your answer.
b) Stephen's height is 1.80 m and his mass is 68.5 kg. He wants to have a BMI of 20.
How many kilograms must he lose to reach a BMI of 20? Show your working.
Answers
Tina =
Tina = (1.56m)
Tina = (1.56m)18.8kg
Tina = (1.56m)18.8kg
Tina = (1.56m)18.8kg
Tina = (1.56m)18.8kg =20.05 BMI
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen=
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80)
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90)
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2 68.5−x
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2 68.5−x
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2 68.5−x =20
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2 68.5−x =20⇒x=3.7
Tina = (1.56m)18.8kg =20.05 BMITina is not underweight because her BMI > 18.5.b. Present BMI of stephen= (1.80) 2 68.5 =21.14⇒ (1.90) 2 68.5−x =20⇒x=3.7solution